Scalar Wave Equation in a Schwarzschild B Archives - Time Travel, Quantum Entanglement and Quantum Computing https://stationarystates.com/tag/scalar-wave-equation-in-a-schwarzschild-b/ Not only is the Universe stranger than we think, it is stranger than we can think...Hiesenberg Mon, 09 Sep 2024 18:25:25 +0000 en-US hourly 1 https://wordpress.org/?v=6.6.2 Scalar Wave Equation in a Schwarzschild Background https://stationarystates.com/cosmology/scalar-wave-equation-in-a-schwarzschild-background/?utm_source=rss&utm_medium=rss&utm_campaign=scalar-wave-equation-in-a-schwarzschild-background Sat, 06 Jul 2024 20:00:20 +0000 https://stationarystates.com/?p=505 Schwarzschild Solution for a Black Hole Scalar Wave Equation in Schwarzschild Background: For the Schwarzschild metric, the scalar wave equation becomes: (1−2GMc2r)−1∂2Φ∂t2−1r2∂∂r(r2(1−2GMc2r)∂Φ∂r)−1r2sin⁡θ∂∂θ(sin⁡θ∂Φ∂θ)−1r2sin⁡2θ∂2Φ∂ϕ2=0.\left(1 – \frac{2GM}{c^2r}\right)^{-1} \frac{\partial^2 \Phi}{\partial t^2} – \frac{1}{r^2} \frac{\partial}{\partial […]

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Schwarzschild Solution for a Black Hole

Scalar Wave Equation in Schwarzschild Background: For the Schwarzschild metric, the scalar wave equation becomes:

(1−2GMc2r)−1∂2Φ∂t2−1r2∂∂r(r2(1−2GMc2r)∂Φ∂r)−1r2sin⁡θ∂∂θ(sin⁡θ∂Φ∂θ)−1r2sin⁡2θ∂2Φ∂ϕ2=0.\left(1 – \frac{2GM}{c^2r}\right)^{-1} \frac{\partial^2 \Phi}{\partial t^2} – \frac{1}{r^2} \frac{\partial}{\partial r} \left( r^2 \left(1 – \frac{2GM}{c^2r}\right) \frac{\partial \Phi}{\partial r} \right) – \frac{1}{r^2 \sin \theta} \frac{\partial}{\partial \theta} \left( \sin \theta \frac{\partial \Phi}{\partial \theta} \right) – \frac{1}{r^2 \sin^2 \theta} \frac{\partial^2 \Phi}{\partial \phi^2} = 0.

3. Separation of Variables: To solve this equation, we often use separation of variables. Let:

Φ(t,r,θ,ϕ)=e−iωtψ(r)rYlm(θ,ϕ),\Phi(t, r, \theta, \phi) = e^{-i\omega t} \frac{\psi(r)}{r} Y_{lm}(\theta, \phi),

where Ylm(θ,ϕ)Y_{lm}(\theta, \phi) are the spherical harmonics and ω\omega is the frequency of the wave.

4. Radial Equation: Substituting this ansatz into the wave equation and simplifying, we obtain the radial equation:

(1−2GMc2r)d2ψdr2+(ω2(1−2GMc2r)−l(l+1)r2−2GMc2r3)ψ=0.\left(1 – \frac{2GM}{c^2r}\right) \frac{d^2 \psi}{dr^2} + \left( \frac{\omega^2}{\left(1 – \frac{2GM}{c^2r}\right)} – \frac{l(l+1)}{r^2} – \frac{2GM}{c^2r^3} \right) \psi = 0.

This is a second-order differential equation for ψ(r)\psi(r), which describes how the scalar field propagates in the Schwarzschild spacetime.

5. Potential Term: The term:

V(r)=(1−2GMc2r)(l(l+1)r2+2GMc2r3),V(r) = \left(1 – \frac{2GM}{c^2r}\right) \left( \frac{l(l+1)}{r^2} + \frac{2GM}{c^2r^3} \right),

acts as an effective potential for the radial part of the wave equation.

Summary

  • The Schwarzschild solution describes the spacetime geometry around a non-rotating, uncharged black hole.
  • The scalar wave equation in this background can be solved using separation of variables, leading to a radial equation with an effective potential.
  • These solutions provide insights into the behavior of fields and waves in the vicinity of a black hole.

 

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