Entanglement Archives - Time Travel, Quantum Entanglement and Quantum Computing https://stationarystates.com/category/entanglement/ Not only is the Universe stranger than we think, it is stranger than we can think...Hiesenberg Mon, 08 Dec 2025 22:45:19 +0000 en-US hourly 1 https://wordpress.org/?v=6.9.1 Partial-Sum Probabilities vs. Bell Correlations https://stationarystates.com/entanglement/partial-sum-probabilities-vs-bell-correlations/?utm_source=rss&utm_medium=rss&utm_campaign=partial-sum-probabilities-vs-bell-correlations Mon, 08 Dec 2025 22:45:19 +0000 https://stationarystates.com/?p=1091 Partial-Sum Probabilities vs. Bell Correlations — Illustrated Partial-Sum Probabilities ⇄ Successive Measurements in Bell Experiments Figure: Left — running-partial-sum Markov transitions; Right — Bell measurement settings and entangled state. (Generated […]

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Partial-Sum Probabilities vs. Bell Correlations — Illustrated



Partial-Sum Probabilities ⇄ Successive Measurements in Bell Experiments


Diagram: partial sums vs Bell experiment

Figure: Left — running-partial-sum Markov transitions; Right — Bell measurement settings and entangled state. (Generated diagram.)

Overview

Both the classical partial-sum process and the quantum Bell experiment produce probabilities for sequences of outcomes.
The useful analogy is that both systems evolve probabilities over a space of possible “paths” (integer sums vs. measurement outcomes). However, the
crucial difference is that Bell correlations require non-classical probability structure: no classical Markov chain or hidden-local-variable model can reproduce them.

1. The Partial-Sum (Markov) Model — short description

Suppose we draw integers uniformly from {1,…,N} with replacement and keep a running sum \(S_k\). The evolution is
classical and Markovian:

\(P(S_k = s) = \sum_{i=1}^{N} P(S_{k-1} = s-i)\cdot \frac{1}{N}.\)
      

To ask for the probability of reaching exactly \(n\) at some step is to condition on allowed paths through the integer-state lattice; paths that overshoot are excluded.
This process is classical: transition probabilities are nonnegative, normalized, and depend only on the previous state (Markov property).

2. Bell (CHSH-style) Experiment — short description

Two distant parties, Alice and Bob, share an entangled state \(\lvert\psi\rangle\). Each party chooses a measurement setting (Alice: \(a\) or \(a’\); Bob: \(b\) or \(b’\))
and obtains outcomes \(A,B\in\{+1,-1\}\). Quantum mechanics predicts joint probabilities

\(P(A,B \mid a,b) = \langle\psi \rvert \; \big(M_A^{(a)} \otimes M_B^{(b)}\big) \; \lvert\psi\rangle,\)

where \(M_A^{(a)},M_B^{(b)}\) are measurement operators (projectors).
      

The key empirical fact: for certain choices of \((a,a’,b,b’)\), the correlations violate the CHSH inequality and reach up to \(2\sqrt{2}\) (Tsirelson bound).

3. Classical Hidden-Variable / Markov-Factorization Assumption

A classical model with a hidden variable \(\lambda\) (and local Markov-like transitions) assumes the joint probability factorizes as:

\(P(A,B \mid a,b) \;=\; \int d\lambda \; \rho(\lambda)\; P(A\mid a,\lambda)\; P(B\mid b,\lambda).\)
      

This expresses locality and a classical probabilistic structure. If such a representation exists, all CHSH-type correlations obey the classical bound of 2.

4. CHSH inequality (derivation sketch)

Define correlators
\(\;E(a,b) = \sum_{A,B=\pm1} AB \, P(A,B\mid a,b).\)
Under the classical factorization with deterministic \(\pm1\) responses (or by convexity for probabilistic responses),
one can show the CHSH combination satisfies:

\(S \;=\; E(a,b) + E(a,b') + E(a',b) - E(a',b') \;\le\; 2.\)
      

The short intuitive proof: for a fixed \(\lambda\) and deterministic outcomes \(A(a,\lambda),B(b,\lambda)\in\{\pm1\}\),
the quantity
\[
Q(\lambda) = A(a,\lambda)\big[ B(b,\lambda) + B(b’,\lambda) \big] + A(a’,\lambda)\big[ B(b,\lambda) – B(b’,\lambda) \big]
\]
can only be \(\pm2\). Averaging over \(\lambda\) yields \(|S|\le 2\).

5. Quantum prediction violates the classical bound

For the two-qubit singlet state and spin (or polarization) measurements at appropriate angles one finds

\(S_{\text{quantum}} = 2\sqrt{2} > 2.\)
      

Therefore no model of the factorized classical form (and hence no classical Markov chain producing local factorized joint probabilities) can reproduce these correlations.

6. Why this forbids any classical Markov-chain representation

A Markov chain (or any classical sequential stochastic process) defines joint distributions built from nonnegative transition probabilities and local conditionalization on prior states.
If you attempt to represent the Bell scenario with a classical Markov chain / path model, you would need to assign joint probabilities
\(P(A,B\mid a,b)\) that simultaneously satisfy all measurement-setting marginals and the factorization/locality condition.
But because quantum correlations violate CHSH, no such global assignment of classical nonnegative transition probabilities exists.

Concretely:

  • Partial-sum Markov processes: probabilities are built from local, stepwise transition kernels (nonnegative, normalized).
  • Any classical hidden-variable or Markov description that respects locality must obey Bell (CHSH) bounds.\li>
  • Quantum correlations (experimentally verified) violate those bounds, so they cannot be written as expectations over local Markov transitions.

7. Side-by-side summary (compact)

Feature Partial-Sum / Markov Bell / Quantum
State space Integer sums, classical lattice Hilbert space (amplitudes)
Allowed transitions Nonnegative transition kernel, Markov Unitary + measurement (non-commuting)
Path weighting Sum of nonnegative path probabilities Amplitude interference (complex), not representable as simple path probabilities
Bell/CHSH Always satisfies CHSH bound \(|S|\le2\) Can achieve \(|S|=2\sqrt2>2\)

8. Intuition: interference & non-commutativity vs. classical conditioning

Classical path models add probabilities for disjoint paths. Quantum mechanics adds complex amplitudes that can interfere, producing correlations that cannot be decomposed into a convex mixture of local deterministic paths.
Mathematically this is tied to the non-commutativity of measurement operators and the fact that a global joint distribution for all possible measurement outcomes (for all settings) that is both local and reproduces quantum marginals does not exist.

9. Optional: short worked example (CHSH angles)

For the singlet state choose measurement directions such that
\(\theta_{a,b}=0^\circ,\; \theta_{a,b’}=90^\circ,\; \theta_{a’,b}=45^\circ,\; \theta_{a’,b’}=135^\circ\).
The quantum correlator for spin-1/2 is \(E(\alpha,\beta) = -\cos(\theta_{\alpha\beta})\).
Then

\(S = -\cos 0^\circ – \cos 90^\circ – \cos 45^\circ + \cos 135^\circ
= -1 – 0 – \tfrac{\sqrt2}{2} + \big(-\tfrac{\sqrt2}{2}\big)
= -2\sqrt2 \)

so \(|S|=2\sqrt2\), violating the classical limit of 2.

10. Final takeaway

The visual/structural analogy is useful: both systems manage probability flow across allowed paths (integer-lattice paths vs. sequences of measurement outcomes). But Bell correlations are fundamentally incompatible with any classical Markov-chain (or local hidden-variable) representation because they violate inequalities (CHSH) that any such classical model must obey. That violation is the signature of quantum non-classicality (entanglement + interference + non-commuting observables).

If you want, I can:

  • Render a tidy SVG version of the diagram optimized for publication,
  • Produce a step-by-step Markov-chain attempt that fails to reproduce a specific quantum dataset, or
  • Turn the mathematical derivation into a printable PDF or slideshow.

Note: the diagram included above was generated in this session; if it doesn’t appear in your environment, I can embed it inline as an encoded image or provide a downloadable link on request.


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Boost of a Singlet Entangled State https://stationarystates.com/entanglement/boost-of-a-singlet-entangled-state/?utm_source=rss&utm_medium=rss&utm_campaign=boost-of-a-singlet-entangled-state Thu, 02 Oct 2025 03:30:53 +0000 https://stationarystates.com/?p=998 Lorentz Boost of a Spin-Singlet: A Worked Example with Wigner Rotations Lorentz Boost of a Spin-Singlet: A Worked Example with Wigner Rotations We show explicitly how a Lorentz boost acts […]

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Lorentz Boost of a Spin-Singlet: A Worked Example with Wigner Rotations




Lorentz Boost of a Spin-Singlet: A Worked Example with Wigner Rotations

We show explicitly how a Lorentz boost acts on a two–spin-1/2 singlet state by inducing Wigner rotations that depend on the particle momenta.
The key takeaway: the full bipartite state remains entangled in every inertial frame, but the distribution of entanglement between spin and momentum,
and therefore the spin-only correlations accessible to a given observer, can change across frames.


1) Setup in the Center-of-Momentum (CM) Frame

Consider two spin-1/2 particles with equal and opposite momenta along the \(z\)-axis in the CM frame:
\(\mathbf{p}_A = +p\,\hat{\mathbf{z}}\), \(\mathbf{p}_B = -p\,\hat{\mathbf{z}}\).
Let the spin state be the singlet:

\[
\lvert \Psi^- \rangle
= \frac{1}{\sqrt{2}}\big(\lvert \uparrow \rangle_A \lvert \downarrow \rangle_B
– \lvert \downarrow \rangle_A \lvert \uparrow \rangle_B\big).
\]

Assume (for clarity) sharply peaked momenta (delta-like wavepackets) so that we can track definite momenta through the boost.


2) Apply a Pure Lorentz Boost Along x

Boost the whole system by rapidity \(\eta\) along the \(x\)-axis, i.e., a boost \(\Lambda(\eta\,\hat{\mathbf{x}})\).
For a particle with 4-momentum \(p^\mu\), a pure boost followed by the standard momentum alignment induces a Wigner rotation
on its spin. Because the two particles carry opposite momenta in the CM frame, they experience opposite Wigner rotation angles.

Let \(\xi\) be the rapidity corresponding to the particle’s CM-frame momentum magnitude \(p\) and mass \(m\):

\[
\cosh \xi = \frac{E}{m}, \qquad \sinh \xi = \frac{p}{m}, \qquad \tanh \xi = \frac{p}{E} = v.
\]

For this geometry (boost along \(x\), momenta along \(\pm z\)), the induced Wi

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Entangled States and Reference Frames https://stationarystates.com/entanglement/entangled-states-and-reference-frames/?utm_source=rss&utm_medium=rss&utm_campaign=entangled-states-and-reference-frames Thu, 02 Oct 2025 03:28:47 +0000 https://stationarystates.com/?p=996   Relativistic Treatment of Entangled Particles Also read – Boost of a singlet entangled state 1. Lorentz Invariance of Entanglement Entanglement is a property of the quantum state as a […]

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Relativistic Treatment of Entangled Particles

Also read – Boost of a singlet entangled state

1. Lorentz Invariance of Entanglement

Entanglement is a property of the quantum state as a whole. If two particles are entangled in one inertial frame,
they are entangled in all inertial frames.

  • Lorentz transformations (boosts and rotations) are unitary transformations on the Hilbert space.
  • Unitary transformations cannot convert an entangled state into a separable one (or vice versa).

Thus, the fact of entanglement is invariant.

\[
|\Psi^-\rangle = \frac{1}{\sqrt{2}}\Big(|\uparrow\rangle_A|\downarrow\rangle_B – |\downarrow\rangle_A|\uparrow\rangle_B\Big)
\]

A Lorentz boost maps spin states to spin states (through Wigner rotations), but does not turn the state into a separable product.

2. What Does Change With Reference Frame?

While entanglement as such is invariant, the manifestation of correlations can change:

  • Spin and momentum entanglement trade-off: In relativistic treatments, spin and momentum are not independent. A Lorentz boost can “mix” these degrees of freedom (via Wigner rotations).
  • Observable correlations: Measurement outcomes depend on the orientation of detectors. In a boosted frame, the effective measurement axis is rotated relative to the particle’s momentum, so the correlations can appear altered.
  • Accessibility of entanglement: If you “trace out” momentum degrees of freedom (because your detectors don’t resolve them), then in some frames you may see reduced spin entanglement—even though the full state is still entangled.

The full quantum state remains entangled, but how much entanglement you observe in a particular subsystem depends on the frame.

3. Relativity of Simultaneity

  • Entanglement correlations are nonlocal, but they don’t imply causal signaling.
  • Different frames disagree on the time ordering of spacelike-separated measurements, but all observers predict the same joint statistics.
  • This is why the no-communication theorem survives relativity.

4. Research Frontiers

  • Relativistic quantum information: Studies how entanglement is affected by boosts, acceleration, and curved spacetime.
  • Unruh effect: Accelerated observers perceive the vacuum as a thermal bath, which can degrade entanglement.
  • Gravitational backgrounds: In curved spacetime, entanglement entropy can change depending on observer horizons (e.g., black holes, Rindler observers).

✅ Answer in one line

Entanglement itself is Lorentz invariant—if two particles are entangled in one frame, they remain entangled in all—
but the type of entanglement (e.g., spin vs momentum) and the measurable correlations can appear different
to observers in different reference frames.

 

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Entangled States, Extra Dimensions and FTL https://stationarystates.com/entanglement/entangled-states-extra-dimensions-and-ftl/?utm_source=rss&utm_medium=rss&utm_campaign=entangled-states-extra-dimensions-and-ftl Sun, 21 Sep 2025 01:59:49 +0000 https://stationarystates.com/?p=972 Entanglement, Extra Dimensions, and Faster-Than-Light Communication Entanglement, Extra Dimensions, and Faster-Than-Light Communication The question of whether extra dimensions (spatial or temporal) accessible to entangled systems could allow faster-than-light (FTL) communication […]

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Entanglement, Extra Dimensions, and Faster-Than-Light Communication




Entanglement, Extra Dimensions, and Faster-Than-Light Communication

The question of whether extra dimensions (spatial or temporal) accessible to entangled systems
could allow faster-than-light (FTL) communication has been considered in various speculative and
theoretical physics works. Short answer: standard quantum mechanics, plus relativity
(and especially the no-communication theorem), strongly argues that no, you can’t use entanglement
to send information FTL — even if one imagines extra dimensions. But there are papers exploring
related ideas, some quite recent, that try to reconcile quantum nonlocality with extra dimensions
or with higher-dimensional spacetime or hidden geometry. Below is a summary and analysis of why
it doesn’t (so far) allow real FTL signaling.


Some relevant published ideas

Paper / Proposal Main idea Does it allow FTL communication? Comments / Challenges
“Quantum entanglement without nonlocal causation in (3,2)” – M. Pettini (2025) A toy model where nonlocal correlations from entanglement are explained via an extra-temporal dimension (more than one time) rather than instantaneous causation in 4D. No. It only reinterprets correlations; does not provide a mechanism for usable FTL signals. Remains a toy model; many assumptions need fleshing out.
“Time-like Extra Dimensions: Quantum Nonlocality, Spin…” – M. Furquan (2025) Proposes spacetime is 6D, with two extra time-like dimensions. Correlations spacelike in 4D may be timelike in 6D. States explicitly that FTL messaging is still impossible; no-communication theorem holds. Issues: physical motivation for extra times, causal stability, experimental consistency.
“Could an extra time dimension reconcile quantum entanglement with local causality?” (Physics World, 2025) Conceptual discussion of extra time dimensions as an explanation for entanglement correlations. No concrete signaling protocol; remains speculative. Multiple time dimensions risk pathologies, instabilities, causality violations.
“Superluminal propagation along the brane in space with extra dimensions” – D.-C. Dai & D. Stojkovic (2023) In braneworld scenarios, signals may leave the 4D brane, travel through the bulk, and return faster than purely 4D geodesics. Some apparent superluminality, but about classical signals, not entanglement. Constrained by higher-dimensional GR and observations; no usable instantaneous messaging.
Other works (e.g., Ge & Kim, 2007) Study how extra spatial dimensions affect entanglement persistence, teleportation fidelity, etc. No Focus on degradation or robustness of entanglement, not superluminal communication.

Why entanglement + extra dimensions ≠ FTL information (so far)

No-communication theorem

In standard QM, the no-communication (or no-signaling) theorem proves that although measurements
on entangled systems cause correlated outcomes, one party cannot control the outcome on their side
in order to send a message to the other side. This theorem is very general. Even if one embeds QM
into a larger theory (extra dimensions, hidden variables, etc.), any proposal allowing control of
outcomes so as to violate no-signaling conflicts with other well-tested principles
(relativistic causality, experimental consistency).

Entangled “state space” vs. physical spatial dimensions

The fact that the quantum state of two entangled particles lives in a Hilbert space whose
dimension is the tensor product of each subsystem’s space does not mean there are extra
spatial dimensions beyond the physical ones. Hilbert-space dimensions are labels for states, not
directions in which particles can move. Just because the full entangled wavefunction is a function
of many coordinates does not make them extra traversable dimensions.

Relativistic causality and locality

Even with extra dimensions, causal structure (light cones) must project consistently onto
4D spacetime. Allowing FTL signals would create paradoxes, e.g., closed timelike curves, unless
further constraints prohibit operational signaling.

Experimental constraints

Numerous Bell-test and quantum optics experiments confirm that entanglement behaves as predicted
by QM, with no evidence for controllable FTL messaging. Any extra-d

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Amplitude in an Entangled Wavefunction https://stationarystates.com/basic-quantum-theory/amplitude-in-an-entangled-wavefunction/?utm_source=rss&utm_medium=rss&utm_campaign=amplitude-in-an-entangled-wavefunction Sat, 30 Aug 2025 23:25:59 +0000 https://stationarystates.com/?p=962     Q&A: What Does the Amplitude Represent for an Entangled Wavefunction? Q1. Since wavefunctions are amplitudes, what does the amplitude represent? 1) Wavefunction as an amplitude The wavefunction Ψ […]

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Q&A: What Does the Amplitude Represent for an Entangled Wavefunction?

Q1. Since wavefunctions are amplitudes, what does the amplitude represent?

1) Wavefunction as an amplitude

  • The wavefunction Ψ is not a probability distribution; it is a complex probability amplitude.
  • For a single particle, |Ψ(x)|² gives the probability density of finding the particle at position x.
  • The phase of Ψ encodes relative information important for interference; it has no direct probability meaning by itself.

So:

  • Amplitude = a complex number attached to each possible configuration.
  • Probability = squared modulus of that amplitude.

Q2. How does this generalize to an entangled pair of particles?

2) Entangled pair case

The joint wavefunction lives in a tensor-product space: Ψ(xA, xB).

  • The amplitude Ψ(xA, xB) is the complex probability amplitude for “A at xA and B at xB simultaneously.”
  • With entanglement, the amplitude cannot factor into single-particle pieces:
    Ψ(xA, xB) ≠ ψA(xA) ψB(xB)
  • Instead, it encodes joint correlations (e.g., large amplitudes only for correlated spin outcomes).

Q3. Physically, what does a particular amplitude mean, and how do phases matter?

3) What the amplitude represents physically

  • An amplitude is the contribution of a specific configuration (e.g., “A here with spin-up, B there with spin-down”) to the overall quantum state.
  • The magnitude squared of that amplitude is the probability of observing that configuration (in the chosen measurement basis).
  • Relative phases between different configurations govern interference and determine correlation patterns under basis changes.

Example (Bell state):

|Ψ⟩ = (1/√2) ( |↑⟩A|↓⟩B − |↓⟩A|↑⟩B )

  • Amplitude for |↑AB is +1/√2.
  • Amplitude for |↓AB is −1/√2.
  • Each squared magnitude equals 1/2 (equal probabilities).
  • The relative minus sign is crucial: it controls the type of correlation seen when measuring along different axes.

Q4. Can you show a visual “amplitude table” for an entangled state?

State: |Ψ⟩ = (1/√2) ( |0⟩A|1⟩B − |1⟩A|0⟩B )

A’s State B’s State Amplitude Probability (|amp|²)
0 0 0 0
0 1 +1/√2 1/2
1 0 −1/√2 1/2
1 1 0 0

Key takeaways

  • The wavefunction assigns a complex amplitude to each joint configuration.
  • Probabilities come from squared magnitudes of those amplitudes.
  • Relative phases (like the minus sign above) do not change raw probabilities for a fixed basis, but they do determine interference and correlation behavior when you change the measurement basis.
  • Entanglement appears because this table cannot be factored into a product of “A-only” and “B-only” parts.

 

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Symmetries in Entangled States https://stationarystates.com/entanglement/symmetries-in-entangled-states/?utm_source=rss&utm_medium=rss&utm_campaign=symmetries-in-entangled-states Sun, 27 Jul 2025 03:55:14 +0000 https://stationarystates.com/?p=955 Symmetries in Entangled States under Bohm’s Quantum Potential (FTL Assumption) Assuming faster-than-light (FTL) communication is possible via Bohm’s Quantum Potential, you’re entering a non-local hidden variable interpretation of quantum mechanics. […]

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Symmetries in Entangled States under Bohm’s Quantum Potential (FTL Assumption)

Assuming faster-than-light (FTL) communication is possible via Bohm’s Quantum Potential, you’re entering a
non-local hidden variable interpretation of quantum mechanics. In that framework—Bohmian Mechanics—the
quantum potential acts instantaneously across spatial distances, coordinating entangled particles.

In such a universe, if FTL influence via the quantum potential exists, Lorentz invariance is broken or modified,
and a preferred foliation of spacetime (absolute simultaneity) must be assumed. Given that, we can explore what
symmetries might still be applicable to entangled states:

1. Permutation Symmetry of Entangled States

  • Entangled states of identical particles are symmetric (bosons) or antisymmetric (fermions) under exchange.
  • This symmetry is preserved even across large spatial separations.

Example:

|Ψ⟩ = (1/√2)(|↑⟩ₐ |↓⟩ᵦ − |↓⟩ₐ |↑⟩ᵦ)

2. Gauge Symmetry

  • The global phase invariance of quantum states (a U(1) symmetry) still holds.
  • The Bohmian wavefunction evolves under Schrödinger dynamics and remains gauge invariant.

3. Non-Relativistic Galilean Symmetry

  • Bohmian mechanics typically violates Lorentz symmetry, but preserves Galilean invariance in the non-relativistic limit.
  • The quantum potential is invariant under Galilean transformations.

4. Time-Reversal Symmetry

  • Bohmian trajectories are deterministic and time-reversible.
  • The Schrödinger equation is time-reversal symmetric (modulo complex conjugation), and so is Bohmian evolution.

5. Configuration Space Symmetry

  • In Bohmian mechanics, the wave function lives in configuration space, not 3D physical space.
  • Entangled states are non-factorizable and inherently nonlocal in this space.

Caveat: Breaking Lorentz Symmetry

  • Allowing FTL interaction via the quantum potential violates Lorentz symmetry, unless a preferred reference frame is introduced.
  • Spatial rotation symmetry (SO(3)) may be preserved, but boost symmetry is broken.

Summary Table

Symmetry Preserved? Notes
Permutation (Exchange) ✅ Important for identical entangled particles
Gauge (U(1)) ✅ Global phase invariance
Galilean ✅ Non-relativistic limit; Bohmian-compatible
Lorentz ❌ Violated by non-local influences
Time-Reversal ✅ Bohmian mechanics is deterministic and reversible
Configuration Space Symmetry ✅ Fundamental in Bohmian interpretation

In Conclusion

If FTL communication via Bohm’s quantum potential exists, the entangled states still obey permutation, gauge, time-reversal, and
configuration-space symmetries
, but Lorentz invariance must be relinquished. In its place, a hidden preferred frame
or foliation of spacetime is assumed. The overall coherence of entangled states is preserved through the nonlocal structure of the
wavefunction in configuration space
, guided by a universal quantum potential.

 

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Two particle wavefuction = 6 spatial dimensions https://stationarystates.com/uncategorized/two-particle-wavefuction-6-spatial-dimensions/?utm_source=rss&utm_medium=rss&utm_campaign=two-particle-wavefuction-6-spatial-dimensions Wed, 25 Jun 2025 19:12:11 +0000 https://stationarystates.com/?p=950   Why a Two-Particle Wavefunction Lives in Six Dimensions — and How That Gives Us Entanglement Ask a beginning student of quantum mechanics where a particle “is,” and they will […]

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Why a Two-Particle Wavefunction Lives in Six Dimensions — and How That Gives Us Entanglement

Ask a beginning student of quantum mechanics where a particle “is,” and they will point to a three–dimensional wavefunction
\psi(\mathbf r) that spreads across ordinary space.
But give that student a second particle, and suddenly the mathematics leaps from three spatial coordinates to six.
Why does a joint wavefunction \Psi(\mathbf r_1,\mathbf r_2) need six coordinates instead of two separate 3-D functions, and what does that have to do with the mystery of entanglement?
This post unpacks the jump from 3 → 6 dimensions and shows how it is the seedbed for quantum correlations no classical story can match.


1. Configuration Space vs. Physical Space

  • Physical space (3-D): (x,y,z) describes where one particle may be found.
  • Configuration space (6-D): (\mathbf r_1,\mathbf r_2)=(x_1,y_1,z_1,x_2,y_2,z_2) describes all at once where two particles may be found.

Mathematically, the Hilbert space for one particle is \mathcal H_1 = L^2(\mathbb R^3).
For two particles we do not create two separate Hilbert spaces floating side-by-side; we take their tensor product:

\displaystyle \mathcal H_{12} = \mathcal H_1 \otimes \mathcal H_2 \;=\; L^2(\mathbb R^3) \otimes L^2(\mathbb R^3) \;\cong\; L^2(\mathbb R^6).

That final isomorphism is why the joint wavefunction must accept six spatial coordinates.
Every point in this 6-D landscape is a pair of positions: “particle 1 is here, particle 2 is there.”


2. Factorable vs. Non-Factorable States

If the two particles are completely independent, their joint wavefunction factorises:

\displaystyle \Psi(\mathbf r_1,\mathbf r_2)= \psi_A(\mathbf r_1)\;\phi_B(\mathbf r_2).

Such a product state carries no inter-particle information; you can talk about each particle separately.
But quantum mechanics allows (and soon demands) something richer: most legitimate states in L^2(\mathbb R^6) cannot be written as a single product.
Whenever \Psi refuses to split this way, the particles are entangled.


3. A Canonical Example: The Spin Singlet

Even when spatial parts factorise, internal degrees of freedom (such as spin) often do not.
The famous singlet state illustrates entanglement using only spin coordinates:

\displaystyle \lvert \Psi_{\mathrm{singlet}}\rangle = \frac{1}{\sqrt2}\Bigl(\lvert\uparrow\rangle_1 \otimes \lvert\downarrow\rangle_2 \;-\; \lvert\downarrow\rangle_1 \otimes \lvert\uparrow\rangle_2\Bigr).

No rearrangement can turn this superposition into a simple product of “state 1” and “state 2.”
Measure particle 1 and particle 2’s outcomes are instantly correlated, even though each individual result is random.
Spatial variables can be entangled the same way; now the correlations involve where the particles show up.


4. Visual Intuition: Mountains in 6-D Space

Picture an ordinary 3-D probability cloud as a fuzzy mountain rising above a map.
For two particles the “mountain” lives over a 6-D map: any ridge, valley, or peak couples the two positions.
A narrow ridge running along the diagonal \mathbf r_1=\mathbf r_2 means “the particles like to be found together.”
A ridge along \mathbf r_1=-\mathbf r_2 would encode anti-correlation.
Those landscapes cannot collapse into two independent 3-D hills unless they are perfectly factorable.


5. Why Six Dimensions Breed Entanglement

  1. Shared mathematical home: Putting both particles in the same function forces us to treat the pair as a single quantum object.
  2. Superposition across pairs: The tensor product space lets us superpose pairs of coordinates, not just individual coordinates. That extra freedom is exactly what makes non-classical correlations possible.
  3. Measurement collapse: When you measure one particle, you slice through the 6-D mountain along a 3-D hyperplane. The remaining slice immediately dictates the other particle’s distribution — giving rise to the “spooky action” Einstein disliked.

6. Takeaways for the Curious Trader of Quanta

  • A joint wavefunction inhabits configuration space — six (or more) spatial dimensions for many-body systems.
  • If that wavefunction factorises, the particles are independent. If not, you have entanglement.
  • Entanglement is therefore not an add-on feature; it is the default landscape whenever a multi-particle wavefunction resists factorisation.
  • Scaling up to N particles pushes you into a 3N-dimensional configuration space, which is why simulating many-body quantum systems is so computationally hard.

Conclusion

Seeing the two-particle state as a single resident of six-dimensional configuration space reframes entanglement as geometry:
when probability mass spreads in directions that couple the coordinates of particle 1 with those of particle 2, the particles are entwined inextricably.
What feels “spooky” in three dimensions is completely natural — even inevitable — in the full 6-D theatre where joint quantum states really live.

 

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GHZ Experiment – Bell’s Theorem https://stationarystates.com/entanglement/ghz-experiment-bells-theorem/?utm_source=rss&utm_medium=rss&utm_campaign=ghz-experiment-bells-theorem Fri, 16 May 2025 04:13:34 +0000 https://stationarystates.com/?p=912 Why the GHZ Test Is Better Than Bell’s Original Setup Also read – Derivation of GHZ 1. Bell’s Test is Statistical — GHZ is Deterministic Bell’s theorem relies on statistical […]

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Why the GHZ Test Is Better Than Bell’s Original Setup

Also read – Derivation of GHZ

1. Bell’s Test is Statistical — GHZ is Deterministic

  • Bell’s theorem relies on statistical inequalities (like CHSH) that require many repeated measurements to build up probabilities.
  • GHZ provides a logical contradiction with local realism in a single set of measurements—no inequalities, no statistics.

👉 GHZ doesn’t rely on experimental loopholes like sampling bias. It’s conceptually sharper.

2. GHZ Reveals Contradictions Without Statistics

  • Bell’s violations are statistical averages (e.g., CHSH up to 2√2 vs classical bound 2).
  • GHZ shows that even one round of measurement contradicts local hidden variable logic.

“You don’t need to trust probabilities—just logic.”

3. It Sharpens the Local Realism Argument

Bell’s theorem leaves room for local realists to argue that violations are statistical anomalies.
GHZ removes that ambiguity completely.

“Even in the best-case, one-shot measurement, your classical logic breaks.”

4. Experimental Simplicity (in Principle)

  • GHZ experiments are harder practically due to needing 3 entangled particles.
  • But you don’t need randomized measurement settings or statistical analysis.

Summary: Why GHZ > Bell (Conceptually)

Feature Bell (2 particles) GHZ (3+ particles)
Relies on statistics? ✅ Yes ❌ No
Needs inequality formulation? ✅ Yes (e.g. CHSH) ❌ No
Logical contradiction? ❌ Not directly ✅ Yes
Requires repeated trials? ✅ Yes ❌ No (in theory)
Conceptual clarity Moderate High – exposes realism flaws

 

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Derivation of GHZ using Dirac Notation https://stationarystates.com/entanglement/derivation-of-ghz-using-dirac-notation/?utm_source=rss&utm_medium=rss&utm_campaign=derivation-of-ghz-using-dirac-notation https://stationarystates.com/entanglement/derivation-of-ghz-using-dirac-notation/#comments Fri, 16 May 2025 04:13:06 +0000 https://stationarystates.com/?p=915   GHZ Derivation Using Dirac Notation The GHZ state provides a clean, deterministic contradiction with local hidden variable theories using quantum mechanics and entangled states. Below is a step-by-step derivation […]

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GHZ Derivation Using Dirac Notation

The GHZ state provides a clean, deterministic contradiction with local hidden variable theories using quantum mechanics and entangled states. Below is a step-by-step derivation using Dirac notation.

🔭 GHZ State

We define the canonical GHZ state for 3 qubits:

    \[ |\text{GHZ}\rangle = \frac{1}{\sqrt{2}} \left( |000\rangle - |111\rangle \right) \]

Each qubit is sent to one of three observers: Alice, Bob, and Charlie.

🧮 Measurement Operators

Each observer measures either:

  • Pauli-X: \sigma_x = |0\rangle\langle1| + |1\rangle\langle0|
  • Pauli-Y: \sigma_y = i|1\rangle\langle0| - i|0\rangle\langle1|

🔸 Example: X_A X_B X_C

Applying X \otimes X \otimes X to the GHZ state:

    \[ X^{\otimes 3} |\text{GHZ}\rangle = \frac{1}{\sqrt{2}} (|111\rangle - |000\rangle) = -|\text{GHZ}\rangle \]

So,

    \[ X_A X_B X_C |\text{GHZ}\rangle = -1 \cdot |\text{GHZ}\rangle \]

🔸 Example: X_A Y_B Y_C

Apply \sigma_x \otimes \sigma_y \otimes \sigma_y to |\text{GHZ}\rangle:

  • \sigma_x |0\rangle = |1\rangle, \sigma_x |1\rangle = |0\rangle
  • \sigma_y |0\rangle = -i|1\rangle, \sigma_y |1\rangle = i|0\rangle

Operating on |000\rangle:

    \[ |000\rangle \mapsto (-i)^2 |111\rangle = -|111\rangle \]

Operating on |111\rangle:

    \[ |111\rangle \mapsto i^2 |000\rangle = -|000\rangle \]

Thus:

    \[ X_A Y_B Y_C |\text{GHZ}\rangle = -(|111\rangle + |000\rangle)/\sqrt{2} = -|\text{GHZ}\rangle \]

But if we define the GHZ state with a minus sign:

    \[ |\text{GHZ}\rangle = \frac{1}{\sqrt{2}}(|000\rangle - |111\rangle) \]

Then:

    \[ X_A Y_B Y_C |\text{GHZ}\rangle = +|\text{GHZ}\rangle \]

✅ Eigenvalue: +1

🧾 Final Quantum Predictions

Operator Eigenvalue (Quantum)
X_A X_B X_C -1
X_A Y_B Y_C +1
Y_A X_B Y_C +1
Y_A Y_B X_C +1

🤯 Local Realism Contradiction

Assume predefined values for each measurement (±1). Then, from the quantum predictions:

    \[ A_X B_X C_X = -1 \\ A_X B_Y C_Y = +1 \\ A_Y B_X C_Y = +1 \\ A_Y B_Y C_X = +1 \]

Multiply the last three:

    \[ (A_X B_Y C_Y)(A_Y B_X C_Y)(A_Y B_Y C_X) = A_X A_Y^2 B_X B_Y^2 C_X C_Y^2 = A_X B_X C_X \]

Since squares of ±1 are 1, this implies:

    \[ A_X B_X C_X = +1 \]

This contradicts the earlier prediction:

    \[ A_X B_X C_X = -1 \]

❌ Logical Contradiction

Local hidden variable theories predict +1, quantum mechanics predicts −1. This contradiction is not statistical—it’s logical and deterministic.

✅ Thus, **local realism is incompatible with quantum mechanics**.

 

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The Aspect Experiment: Quantum Entanglement, Bell’s Theorem, and Reality https://stationarystates.com/entanglement/901/?utm_source=rss&utm_medium=rss&utm_campaign=901 Wed, 07 May 2025 14:51:53 +0000 https://stationarystates.com/?p=901 The Aspect Experiment: Quantum Entanglement, Bell’s Theorem, and Reality In 1982, Alain Aspect conducted one of the most famous experiments in modern physics — a test of quantum entanglement that […]

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bell experiment
bell experiment

The Aspect Experiment: Quantum Entanglement, Bell’s Theorem, and Reality

In 1982, Alain Aspect conducted one of the most famous experiments in modern physics — a test of quantum entanglement that challenged the very nature of reality. This experiment sought to determine whether the world is governed by local, deterministic rules (as Einstein believed), or if the universe allows for non-local, instantaneous connections (as quantum mechanics predicts).

🔍 The Goal

The goal of the Aspect experiment was to test Bell’s inequalities using entangled photons. If quantum mechanics is correct, these inequalities would be violated. If Einstein’s local realism holds, the inequalities should stay intact.

🧪 Experimental Setup

Aspect’s team produced entangled photons using calcium atoms. These photons traveled in opposite directions to two detectors equipped with rapidly switching polarizers. The angle of these polarizers changed quickly and randomly after the photons were emitted — ensuring that no “signal” could travel between them and influence the outcome.

Diagram of the Aspect experiment

⚙ Technical Innovations

  • Time-varying analyzers: Polarizers switched during the photons’ flight, ensuring no local signal could coordinate the outcomes.
  • Cascade photon pairs: Emitted by calcium atoms in entangled states.
  • Measurement of correlation vs. angle: Quantum mechanics predicts a cos²(θ) correlation; local realism predicts a linear falloff.

📈 The Result

Aspect’s experiment violated Bell’s inequalities in agreement with quantum predictions. This proved that:

  • Local hidden variable theories cannot explain quantum correlations.
  • Quantum mechanics allows for non-local effects.
  • Nature may be fundamentally probabilistic.

🌀 Visualizing the Quantum

Aspect’s findings supported the Wheeler-Feynman absorber theory — a time-symmetric model where particles send and receive waves both forward and backward in time. This framework explains how two particles can correlate outcomes without communicating in the classical sense.

🔐 Loopholes and Beyond

Aspect’s experiment addressed the locality loophole using fast switching. Later experiments would close the detection loophole and implement quantum random number generators to ensure complete independence between measurements.

🌌 Conclusion

The Aspect experiment is a cornerstone of quantum physics. It revealed a universe where entanglement is real, locality can be violated, and reality isn’t quite what it seems. It opened the door to quantum information science and forced physicists and philosophers alike to rethink the fabric of the cosmos.

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